Problem Statement
In computer science, a stack or LIFO (last in, first out) is an abstract data type that serves as a collection of elements, with two principal operations: push, which adds an element to the collection, and pop, which removes the last element that was added.(Wikipedia)
A string containing only parentheses is balanced if the
following is true: 1. if it is an empty string 2. if A and B are correct, AB is
correct, 3. if A is correct, (A) and {A} and [A] are also correct.
Examples of some correctly balanced strings are:
"{}()", "[{()}]", "({()})"
Examples of some unbalanced strings are: "{}(",
"({)}", "[[", "}{" etc.
Given a string, determine if it is balanced or not.
Input
Format
There will be multiple lines in the input file, each having a
single non-empty string. You should read input till end-of-file.
The part of the code that handles input operation is already
provided in the editor.
Output
Format
For each case, print 'true' if the string is balanced, 'false'
otherwise.
Sample
Input
{}()
({()})
{}(
[]
Sample
Output
true
true
false
true
import java.util.*;
class Solution{
static boolean
validateExpression(String str){
char[]
chrArray=str.toCharArray();
int
par=0,cur=0,bra=0;
for(int
i=chrArray.length-1;i>=0;i--){
if(chrArray[i]==')'){
par++;
}else
if(chrArray[i]=='}'){
cur++;
}else
if(chrArray[i]==']'){
bra++;
}
if(chrArray[i]=='('){
par--;
}else
if(chrArray[i]=='{'){
cur--;
}else
if(chrArray[i]=='['){
bra--;
}
}
return
par==bra && bra==cur;
}
public static void
main(String []argh)
{
Scanner sc = new
Scanner(System.in);
while
(sc.hasNext()) {
String
input=sc.next();
//Complete
the code
System.out.println(validateExpression(input));
}
}
}
Input
(stdin)
{}()
({()})
{}(
[]
Your Output (stdout)
true
true
false
true
Expected Output
true
true
false
true
• Score: 20.00/20.00
Test Case #0: 0.08s
Test Case #1: 0.08s
Test Case #2: 0.08s
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