Skip to main content

Tape Equilibrium : Minimize the value |(A[0] + ... + A[P-1]) - (A[P] + ... + A[N-1])|.

Task description
A non-empty zero-indexed array A consisting of N integers is given. Array A represents numbers on a tape.
Any integer P, such that 0 < P < N, splits this tape into two non-empty parts: A[0], A[1], ..., A[P − 1] and A[P], A[P + 1], ..., A[N − 1].
The difference between the two parts is the value of: |(A[0] + A[1] + ... + A[P − 1]) − (A[P] + A[P + 1] + ... + A[N − 1])|
In other words, it is the absolute difference between the sum of the first part and the sum of the second part.
For example, consider array A such that:
A[0] = 3 A[1] = 1 A[2] = 2 A[3] = 4 A[4] = 3We can split this tape in four places:
  • P = 1, difference = |3 − 10| = 7 
  • P = 2, difference = |4 − 9| = 5 
  • P = 3, difference = |6 − 7| = 1 
  • P = 4, difference = |10 − 3| = 7 
Write a function:
class Solution { public int solution(int[] A); }
that, given a non-empty zero-indexed array A of N integers, returns the minimal difference that can be achieved.
For example, given:
A[0] = 3 A[1] = 1 A[2] = 2 A[3] = 4 A[4] = 3the function should return 1, as explained above.
Assume that:
  • N is an integer within the range [2..100,000];
  • each element of array A is an integer within the range [−1,000..1,000].
Complexity:
  • expected worst-case time complexity is O(N);
  • expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.

class Solution {
public int solution(int[] A) { // write your code in Java SE 8 int len=A.length; int sum=0; for(int i=0;i<len;i++){ sum=sum+A[i]; } int diff=0; int retValue=0; int diffS=0; for(int i=0;i<len-1;i++){ diffS=diffS+A[i]; diff=sum-diffS; diff=Math.abs(diff-diffS); if(retValue==0) retValue=diff; if(retValue>diff) retValue=diff; } return retValue; } }


83%                                                        83 out of 100 points







Detected time complexity:
O(N)

expand allExample tests
example 
example test
OK
expand allCorrectness tests
double 
two elements
OK
simple_positive 
simple test with positive numbers, length = 5
OK
simple_negative 
simple test with negative numbers, length = 5
OK
small_random 
random small, length = 100
OK
small_range 
range sequence, length = ~1,000
OK
small 
small elements
OK
expand allPerformance tests
medium_random1 
random medium, numbers from 0 to 100, length = ~10,000
OK
medium_random2 
random medium, numbers from -1,000 to 50, length = ~10,000
OK
large_ones 
large sequence, numbers from -1 to 1, length = ~100,000
WRONG ANSWER 
got 2 expected 0
large_random 
random large, length = ~100,000
OK
large_sequence 
large sequence, length = ~100,000
OK
large_extreme 
large test with maximal and minimal values, length = ~100,000
WRONG ANSWER 
got 2000 expected 0

Comments

Popular posts from this blog

Java Interface

Problem Statement A Java interface can only contain method signatures and fields. Interface can be used to achieve polymorphism. In this problem you will practice your knowledge on interfaces. You are given an interface   AdvancedArithmetic   which contains a method signature   public abstract int divisorSum(int n) . You need to write a class called MyCalculator which implements the interface. divisorSum   function just takes an integer as input and return the sum of all its divisors. For example divisors of 6 are 1,2,3 and 6, so   divisorSum   should return 12. Value of n will be at most 1000. Read the partially completed code in the editor and complete it. You just need to write the MyCalculator class only.   Your class shouldn't be public. Sample Input 6 Sample Output I implemented: AdvancedArithmetic 12 Explanation Divisors of 6 are 1,2,3 and 6. 1+2+3+6=12. import java.util.*; interface AdvancedArithmetic{   public abstract int divisorSum(int n

Problem: Java Exception Handling

Problem Statement Create a class myCalculator which consists of a single method power(int,int). This method takes two integers,   n   and   p , as parameters and finds   n p . If either   n   or   p   is negative, then the method must throw an exception which says "n and p should be non-negative". Please read the partially completed code in the editor and complete it. Your code mustn't be public. No need to worry about constraints, there won't be any overflow if your code is correct. Sample Input 3 5 2 4 -1 -2 -1 3 Sample Output 243 16 java.lang.Exception: n and p should be non-negative java.lang.Exception: n and p should be non-negative import  java.util.*; class myCalculator{     int power(int n,int p) throws java.lang.Exception{         int power=1;         while(p>0){             power=power*(n);             p--;         }                 if(n==0) power=0;                if(n<0 | p<0){       

Google Cloud Shell | Delete instance